■예 1_2_18  ||  에러발생 예제_1
SELECT  T1.SABUN, T1.NAME, T1.AGE, T1.PHONE,
          T2.SABUN, T2.ACAD_ABILITY, T2.MAJOR_STUDY, T2.GRAT_YM,
          T3.ACAD_ABILITY
FROM   TABLE_1 T1, TABLE_2 T2, TABLE_3 T3
WHERE  T1.SABUN = T2.SABUN(+)
   AND  T2.ACAD_ABILITY(+) = '대졸'
   AND  T2.ACAD_ABILITY(+) = T3.ACAD_ABILITY(+);

■예 1_2_19  ||  에러발생 예제_2
SELECT  T1.SABUN, T1.NAME, T1.AGE, T1.PHONE,
          T2.SABUN, T2.ACAD_ABILITY, T2.MAJOR_STUDY, T2.GRAT_YM,
          T3.ACAD_ABILITY
FROM   TABLE_1 T1, TABLE_2 T2, TABLE_3 T3
WHERE  T1.SABUN = T2.SABUN(+)
   AND  T2.ACAD_ABILITY(+) = '대졸'
   AND  T2.ACAD_ABILITY(+) = T3.ACAD_ABILITY;

■예 1_2_20  || OUT JOIN의 올바른 예 1
SELECT  TT2.SABUN, TT2.ACAD_ABILITY, TT2.MAJOR_STUDY, TT2.GRAT_YM,
          TT3 .GRADE_NUM,
          DECODE(TT3.GRADE_NUM, NULL, 100, TT3.GRADE_NUM) AS T_GRADE_NUM
FROM TABLE_2 TT2, TABLE_3 TT3
WHERE TT2.ACAD_ABILITY = TT3.ACAD_ABILITY(+);

■예 1_2_21  ||  OUT JOIN의 올바른 예 2
SELECT  T1.SABUN, T1.NAME, T1.AGE, T1.PHONE,
          T2.SABUN, T2.ACAD_ABILITY, T2.MAJOR_STUDY, T2.GRAT_YM,
          T2.ACAD_ABILITY, T2.GRADE_NUM, T2.T_GRADE_NUM
FROM  TABLE_1 T1,
         (
           SELECT  TT2.SABUN, TT2.ACAD_ABILITY, TT2.MAJOR_STUDY,
                     TT2.GRAT_YM, TT3.GRADE_NUM,
                     DECODE(TT3.GRADE_NUM,NULL,100,TT3.GRADE_NUM) AS T_GRADE_NUM
           FROM TABLE_2 TT2, TABLE_3 TT3
           WHERE TT2.ACAD_ABILITY = TT3.ACAD_ABILITY(+)
         ) T2
WHERE  T1.SABUN = T2.SABUN(+);